今天遇到一个很大的JSON包转为字典后每次获取里面的值相对来说比较麻烦,搜索后发现可以如下解决
# -*- coding:utf-8 -*-
# 2018-03-29 21:17:58
import json
class Dict2Cls(object):
def __init__(self, d):
for a, b in d.items():
if isinstance(b, (list, tuple)):
setattr(self, a, [Dict2Cls(x) if isinstance(x, dict) else x for x in b])
else:
setattr(self, a, Dict2Cls(b) if isinstance(b, dict) else b)
class Struct(object):
def __init__(self, data):
for name, value in data.items():
setattr(self, name, self._wrap(value))
def _wrap(self, value):
if isinstance(value, (tuple, list, set, frozenset)):
return type(value)([self._wrap(v) for v in value])
else:
return Struct(value) if isinstance(value, dict) else value
json_data = open('https://pemako.github.io/assets/data/json.data','r')
#s = Dict2Cls(json.loads(json_data.read()))
s = Struct(json.loads(json_data.read()))
print(s.result.pageInfo.bg_time)
print(s.result.pageInfo.directory[0].title)
上述两种方式均可完成,还有更多的方式,均是利用把DICT 进行循环迭代为类中的属性
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